5x^2=-35x+30=0

Solution for 5x^2=-35x+30=0 equation:

5x^2=-35x+30=0

We move all terms to the left:

5x^2-(-35x+30)=0

We get rid of parentheses

5x^2+35x-30=0

a = 5; b = 35; c = -30;
Δ = b2-4ac
Δ = 352-4·5·(-30)
Δ = 1825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1825}=\sqrt{25*73}=\sqrt{25}*\sqrt{73}=5\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-5\sqrt{73}}{2*5}=\frac{-35-5\sqrt{73}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+5\sqrt{73}}{2*5}=\frac{-35+5\sqrt{73}}{10}
$